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What is the procedure to calculate the actual losses of Passive filter in watts.

Below is the example to calculate the actual losses of Passive filter in watts.
 
Passive filter VW3A4621 with motor 2.2KW and main supply 400V
 
Line current with passive filter given at catalogue is 5A
 
The power absorbed= Pa = U*I*1.73 = 400*5*1.73=3460W
 
Efficiency of passive filter  = > 0.98 = (Pa - PLoss) / Pa
 
So PLoss of passive filter= 70W
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